how to transfer name to address without updating values

[georgem]

I would like to send a name to some address, but the values (ip, dns) don't need to be changed. Only the owner (address)

I understand that the command is:

namecoind name_update d/<name> <value> <address>

So what do I have to type into <value> to not have it be changed at all?
Maybe:

namecoind name_update d/<name> "" <address>

?

Thanks everybody.

[biolizard89]

I would like to send a name to some address, but the values (ip, dns) don't need to be changed. Only the owner (address)

I understand that the command is:

namecoind name_update d/<name> <value> <address>

So what do I have to type into <value> to not have it be changed at all?
Maybe:

namecoind name_update d/<name> "" <address>

?

Thanks everybody.

Why not just type in the old value again? As an aside, I think namecoin-qt makes this easy.

[georgem]

Well ofcourse this is the obvious answer, I should have mentioned that that's NOT what I was looking for.

I am more looking for something like a "null" value.

what happens when I tell namecoind that value is "" ? Does it erase the value?
I assume so.

What is the general way when you want to skip a parameter (but want to use the following parameter) in linux shell?

[georgem]

Why not just type in the old value again? As an aside, I think namecoin-qt makes this easy.

It's for a bitdomain registration site I am working on.

[biolizard89]

I don't think there's a way to skip parameters in a Linux shell. You can give it a blank parameter (""), but that will clear the value from the name, not leave it intact. Is there a reason you can't use namecoind's API to get the existing value before you update it?

[georgem]

No there is no particular reason.

I was just hoping that an extra easy way exists to make the transfer.

Thanks anyway.